Question

A stone is thrown in a verticallyupward direction with a velocity of 5m/s.If the acceleration of the stone during its motion is 10m/s^2 in downward direction,what will be the height attained by the stone and how much time will it take to reach?

$t = v - u \div a$
$s = ut + 1 \div 2a {t}^{2}$

Answer 1

hope this helps you.....