Question

A stone is thrown in such a manner that it would just hit a bird at the top of a tree and afterwards reach a maximum height double that of a tree .if at any moment of throwing the stone the bird flies away horizontally with constant velocity and the stone hits the bird after some time .the ratio of horizontal velocity of stone to that of bird is 1/n+1/root x .find 2n

Answer 1

For the stone:  uy = vertical speed             ux = horizontal speed
Let the height of the tree = h           max height reached = 2h
=>  uy^2 = 2 (2h) g = 4 h g    --- (1)

Let the speed of the bird be v.
The stone and bird meet at height y = h, two times t1 and t2.

y =uy t - 1/2 g t²  
=> h = 2√(hg) t - 1/2 g t²
=> t1 = √(2h/g) * [√2 - 1]                 t2 = √(2 h/g) * [√2 + 1 ]

at t = t1, the stone travels a distance = ux * t1
at t = t2, the stone travels a distance = ux * t2 = ux * t1 + v * t2

so   ux / v = t2/(t2 - t1) = (√2 + 1)/2 = 1/√2   + 1/2

So  n = 2  and  2n = 4

Answer 2

Answered

A stone is thrown in such a manner that it would just hit a bird at the top of a tree and afterwards reach a maximum height double that of a tree .if at any moment of throwing the stone the bird flies away horizontally with constant velocity and the stone hits the bird after some time .the ratio of horizontal velocity of stone to that of bird is 1/n+1/root x .find 2n

Ans : 4