Question

A stone is thrown in vertically upward direction with a velocity of 5 ms. If the acceleration
of the stone during its motion is 10 ms in the downward direction, what will be the height
attained by the stone and how much time will it take to reach there?



ANSWER IT..... Please please...

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Answer 1

Step-by-step explanation:

$u=5ms^1$

$v=0$

$a=10ms^{-2}$

$s=?$

$t=?$

i) $v=u+at$

$0=5+(-10)t$

$-5=10t$

∴$t=\frac{5}{10}=0.5$sec

$t=0.5s$

ii) $v^2-u^2=2as$

$(0)2-(5)^2=2(-10)*s$

$-25=-20*s$

∴$s=\frac{25}{20}=1.25m$

$s=1.25m$

Answer 2

If a body is thrown vertically upwards with an initial velocity "u" to a height "h", then there will be retardation, that is acceleration will be negative.

When it will come downwards, its direction of motion will also be downwards, i.e., towards the earth's gravitational field and hence, at that time the acceleration produced is actually acceleration due to gravity which is denoted by "g".

As a result, the equations will be :

(1) v = u - gt

(2) h = ut - 1/2 gt²

(3) v² = u² - 2gh

Because the acceleration is due to gravity and gravity is in downward direction whereas the actual direction of motion is upwards. Since, the direction are different, acceleration due to gravity will be negative.