Math, asked by jhunrhox08, 5 months ago

A stone is thrown straight up into the air with an initial Velocity of 15m/s. How long does it take to reach the highest point.?

Answers

Answered by rahullahoti233
0

Step-by-step explanation:

A stone is thrown vertically upwards with an initial velocity of 14m/s.

since the velocity at top is zero.

t=

a

v−u

=

9.8

14

=1.43sec

The time taken by the stone to strike the ground will be 2t=2×1.43

t

=2.86sec

Answered by shreyaskulkarni04
1

Answer:

Time = 1.53 seconds

Step-by-step explanation:

Initial velocity, u=15m/s

Final velocity, v=0 ( because at the highest point v will be 0)

a= -g = -9.8m/s²

so

from v=u+at we can find the time taken 't'

this can also be written as v=u+gt as a= -g

so,

0=15+(-9.8)×t

-15 = -9.8t

t = 15/9.8

so, t = 1.53 seconds.

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