Question

A stone is thrown up to a height of 150 m with a velocity of 30m/s after which it falls back to the earth. Calculate u, v, t for going up, t for going down, total distance, total time. plzz show the full calculations

Answer 1

ANSWER

Let u be the initial velocity and h be the maximum height attained by the stone.

v

1

2

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

100=u

2

−10h ....(i)

Again at height h,

v

2

2

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m