Question

a stone is thrown up with a speed 80m/s. calculate maximum height applied by it​

Answer 1

Answer:

taking g = 10 m/s²

h = v²/2g

h = 80²/ 20

h = 320 m

The question asked is probably wrong .but this may be the probable answer

Answer 2

Answer:

160m

Explanation:

we know,

maximum range of projectile is=$\frac{u^{2} }{g}$

                                       =$\frac{80^{2} }{10}$

                                        =6400/10=640m

max. height (H)=R/4

                        =640/4=160m