A stone is thrown upward with a vertical velocity of 49 m/s .In what yime it will return to the gtound
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let u = 49m/s
v = 0m/s at highest point
h = vertical height
a = -g =-9.8m/s^2
v=u+at
0m/s = 49m/s -9.8m/s^2×t
t=(49÷9.8)s
t=5 sec
T=Total time =time of ascent + time of descent
T=10 sec
v = 0m/s at highest point
h = vertical height
a = -g =-9.8m/s^2
v=u+at
0m/s = 49m/s -9.8m/s^2×t
t=(49÷9.8)s
t=5 sec
T=Total time =time of ascent + time of descent
T=10 sec
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