Question

A stone is thrown upward with an initial velocity of 40 ms. Calculate the maximum height reached, the net displacement and total distance.

Answer 1

Answer:

80 m, 0 m, 160 m respectively

Explanation:

Maximum height can be calculated by using following equation of motion

• S = (v² - u²) / (2a)

H = [(0² - 40²) / (2 × -10)] m

= (1600/20) m

= 80 m

Displacement = Shortest distance between initial and final position

Stone reaches its initial position when thrown vertically upwards. Hence, displacement is zero

Distance = Total length of the path followed

= 2 × Maximum Height

= 2 × 80 m

= 160 m

Answer 2

Answer:

distance = displacement

Hmax = u² / 2g

u = 40

g = 10 m/s²

Hmax = 1600 / 20

          = 80 m

distance = displacement = Hmax = 80 m

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