Math, asked by neharaichandel, 1 year ago

aarushi teacher's age is four times of aarushi's age .on adding 26 both of their ages;teacher's age is becomes double of aarushi ' s age .Find the ages of both of them.


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Answers

Answered by Nova505
1

let aarushi's age be x yrs

∴teacher's age is 4x yrs

by given condition,

4x+26 = 2(x+26)

∴4x +26 = 2x+52

∴4x - 2x = 52 - 26

∴2x = 26

∴x = 13

4x = 13*4 = 52

∴aarushi's age is 13 yrs and teacher's age is 52 yrs


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Answered by xishitaghoshx
4
Let Aarushi's age be x
Therefore, Aarushi's teacher's age= 4x

Condition-
Aarushi's age = x+26
Aarushi's teacher's age= 4x+26

Equation- 4x+26= 2(x+26)
4x+26= 2x + 52
4x-2x= 52-26
2x = 26
x= 26/2
Therefore, x= 13.

Aarushi's age= x= 13 years
Aarushi's teacher's age= 4x= 4×13= 52 years

Done. Hope Im right..

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