A stone is thrown upward with velocity of 72 km per hr. If the air resistence is neglected , find the maximum height traveelled by it and time taken for it to return to the ibitial position
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initial velocity u=72KMPH =20m/s.
velocity at maximum height v=0
g=9.8m/s^2 or g=10m/s^2
v^2 -u^2 = -2gH
H= u^2/2g = 20x20/(2x10)=20 m.
,time taken t=2u/g = 2x20/10 =4s.
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