If x = 1 + √2 then show that (x - 1 \ x)³ = 8
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1/x=1/(1+√2)=√2-1)/{√2+1)(√2-1)}
=(√2-1)/(2-1)=√2-1
{(x-1/x)}^3={(√2+1)-(√2-1)}^3
={√2+1-√2+1)^3=(2)^3=8
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