A stone is thrown upwards with a speed v from the top of a tower. It reaches the ground with a velocity 3v. What is the height of the tower?
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Answer:
height=4v
Explanation:
u=v
v=3v
a= (v-u )/t
a=(3v-v)/2=2v/2
a= v ------- eq1
put values of a from eq 1 and values of u and v in above eq
9v^2 - v^2= 2v x s
8v^2/2v=s
s=4v
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