Question

A stone is thrown upwards with a speed v from the top of a tower. It reaches the ground with a velocity 3v. What is the height of the tower?

Answer 1

Answer:

height=4v

Explanation:

u=v

v=3v

a= (v-u )/t

a=(3v-v)/2=2v/2

a= v ------- eq1

${v }^{2} - {u}^{2} = 2as$

put values of a from eq 1 and values of u and v in above eq

${(3v)}^{2} - {v}^{2} = 2v \: \times s$

9v^2 - v^2= 2v x s

8v^2/2v=s

s=4v