Question

father is 24 years older than his daughter .in 4 years,he will be thrice as old as his daughter.find their present ages

Answer 1

Let the present age of father be x yrs
And the present age of daughter be y yrs

ATQ
x = y+24
or
x-y = 24 -------------------i

After 4 years
Father's age = (x+4) yrs
Daughter's age = (y+4) yrs

(x+4) = 3(y+4)
x+4 = 3y+12
=> x-3y = 8 -----------------ii

Substituting the value of x from i into ii

y+24 -3y = 8
=> -2y = 8-24
=> y = 16

x= y+24
= 16+24
= 40

Therefore, the present age of Father is 40 years and the present age of daughter is 16 years.

HOPE IT HELPS YOU !!!!

Answer 2

Let the present age of daughter is 'x'.

Then, the present age of father is x + 24.

4 years hence:

⇒ Age of daughter = x + 4.

⇒ Age of father = x + 24 + 4 = x + 28.

Now,

Given that In 4 years, he will be thrice as old as his daughter.

⇒ x + 28 = 3(x + 4)

⇒ x + 28 = 3x + 12

⇒ 2x = 16

⇒ x = 8.

Then,

⇒ x + 24

⇒ 8 + 24

⇒ 32.

Therefore,

Present age of Daughter = 8 years.

Present age of Father = 32 years.

Hope this helps!