a stone is thrown upwards with a velocity of 40m/s and is caught back. taking g=10m/s², calculate the maximum height reached by the stone .
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The maximum height is calculated as h = u²/2g.
Therefore H = (40)²/2*10 = 80m.
Therefore H = (40)²/2*10 = 80m.
Answered by
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Answer:
The maximum height is calculated as h=u^2/g.
Therefore H =(40)^2/2×10=80m.
Explanation:
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