Question

A stone is thrown upwards with a velocity of 72 km/hr. if air resistance is neglected, find the maximum height travelled by it and the time taken for it to return to the initial position​

Answer 1

Answer:

the initial speed is

Vo = 72 km / h = 72 / 3.6 = 20 m / sec

if there is no friction and I consider the isolated system then the conservation of Mechanical Energy is worth

Total energy = constant = initial kinetic energy = final gravitational potential energy

1 / 2mVo ^ 2 = mgh

so I simplify m

h = Vo ^ 2/2 * g = 20 ^ 2/2 * 9.81 = 20.38 meters ( in Earth )

Please mark me as brainliest

Thank you and have a nice day