Question

a stone is thrown upwards with velocity v at the half the height ots velocity will be

Answer 1

when a stone thrown upward then the velocity of the stone is decreases instantally and at point these velocity is stop deu to gravitational field
and when the stone is return towards the earth then velocity of ston is high and at a half its velocity high comparison with velocity is goes towards sky

Answer 2

Answer:

( v/ root2)

Explanation:

Total height it traversed =>

0^2 = v^2 – 2gH

H = v^2/2g...............................(1)

At half the height.

v’^2 = v^2 – 2g(H/2)

v’^2 = v^2 – v^2/2 = > v^/2 {from eqn. (1)}

v’ = v/root(2) m/s