Question

A stone is thrown upwrd speed u from top of the tower reach velocity 3u

Answer 1

S = (v^2 - u^2) / (2a)

H = ((3u)^2 - u^2) / (2g)

= (9u^2 - u^2) /(2g)

= 8u^2 / (2g)

= 4u^2 / g

Height of the tower is 4u^2 / g

Answer 2

$\large{\mathbb{\red {ANSWER }}}$❤

Solution: The final and initial velocity of the stone has been provided as 3u and u respectively. As the stone is falling down from upward, so the acceleration will be equal to “acceleration due to gravity”.