Question

a stone is thrown vertically from the top of the tower with a velocity of 5ms^-1 and hits the ground after 8 seconds then what is the height of the tower. plz tell quickly ​

Answer 1

Answer:

Let us consider velocity of the stone at the top of the tower is u and the final velocity as v. Since the stone is travelling towards the ground, therefore acceleration is equal to gravity g =9.8m/s² and time is t.

According to one of the kinematic equations

s=ut+1/2at²

Where s is the distance.

s=(5*8)+1/2(9.8*8²)

s=40+1/2(627.2)

s=40+313.6

s=353.6

Therefore the height of the tower is 353.6 metres

Answer 2

Answer:

360 meters

Step-by-step explanation:

Let the initial velocity of the stone = u = 5ms^-1

Acceleration due to gravity = 10 ms^-2

Time = 8 seconds

Height of the tower = S meters.

We know that, S= ut + 1/2 at^2

Putting values, S= 5×8 + 1/2 ×10×8×8

= 40 + 320

= 360 meters

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