Question

A Stone is thrown vertically opposite side from a building of 96 feet height with a intial velocity of 116 feet per second the acceleration due to gravity is 32 feet per second square then after how many seconds the stone will reach the ground

Answer 1

Answer:

1)21x{27-(-5)}is not equal to {(21×27)+21×(-5)} Step-by-step explanation:

1)21x(27-(-5)=672 And [(21x27)+21x(-5)3=462

Answer 2

Answer:

Let u be the initial velocity and h be the maximum height attained by the stone.

v

1

2

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

100=u

2

−10h ....(i)

Again at height h,

v

2

2

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m