In the picture, o is the centre of the circle
and A,Band C and are points
Prove
that LOAC+ LABC =90?
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Answer:
In that circle
if c is the centre of circle ...
and also midpoint of ∆ABC ,
then,
all the angles of the triangle are equal ...
let angles be x ,
then
x+x+x=180°
3x=180°
x=180°/3
x=60°
thus...
angle A,B and C = 60°
AO is angle bisector of angle BAC,
thus,
angle OAC = ½ BAC
= ½60
= 30°
therefore,....
angle OAC + angle ABC = 30 + 60
= 90°
thus proved...
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