Question

a stone is thrown vertically uowards.it decelerates at a rate of 9.8m/s^2.it reaches a greatest height of 16.53 m.calculate its initial speec​

Answer 1

Answer: Given :

a = (-9.8) m/sec^2

s = 16.53m

v = 0m/sec

u = ?

Explanation: By formula

v^2 = u^2 +2as

0 = u^2 + (-323.988)

u = 17.99 m/sec