Question

Find the value of k for which x-1/2 is a factor of polynomial p(x)=x^3+k is given by

Answer 1

For x(-1/2) = 0

So (-1/2)^3 +k =0

K= 1/8

Answer 2

Answer:

p(1/2) = (1/2)^3+k

p(1/2) = 1/8+k

p(1/2) = 0

1/8+k = 0

k = 0×8/1

k = 0