Question

A stone is thrown vertically up from the top of a tower 70 m height with a velocity of 19.2 m/s.

Determine its position and velocity when t = 6 seconds.​

Answer 1

Answer:

solved

Explanation:

time for max height is t1 = u/g = 1.92 sec

time to reach top of tower again = 2t1 = 3.84 sec

remaining time = 6-3.84 =2.16 sec

position ( from Ground Surface) is =70-( ut +gt²/2 )= 70 -(19.2×2.16 + 5×2.16²)

= 70 - 64.8 = 5.2 m.

velocity = u + gt = 19.2 + 21.6 = 40.8 m/s