Question

A stone is thrown vertically up initial velocity 14m/s find maximum height

Answer 1

Hi friend
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Your answer
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Initial velocity = u = 14 m/s

Final velocity = v = 0 m/s [Because the stone will come to rest at a height.]

Acceleration = a = g = - 9.8 m/s² [Acceleration due to gravity taken negative because stone is thrown upwards .]

Now,
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Using formula : - v² - u² = 2as

=> v² - u² = 2gs [Because a = g.]

=> (0)² - (14)² = 2 × ( - 9.8) × s

=> - 196 = - 19.6 × s

=> s = 196/19.6

=> s = 10 m

Therefore,
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The stone acquire a height of 10m.

HOPE IT HELPS

Answer 2

Hi there !!
Here's your answer

Given,

The initial Velocity of the stone = 14m/s

Final velocity = 0m/s ( since when the stone will fall down, at one point, it will be at rest)

Acceleration due to gravity = -9.8m/s²( the motion is downward (retardation)

Maximum height = s

Using the equation of motion,

2as = v² - u²

2 × -9.8 × s = (0)² - (14)²

-19.6 × s = 0 - 196

-19.6s = -196

$s = \frac{ - 196}{ - 19.6} m$
s = 10m

Thus,

the stone acquired the height of 10m