Question

a stone is thrown vertically up words with a velocity of 40m/s and is caught back taking g= 10m/s*s calculate the maximum height reached by the stone what is the net displacement and total distance covered by the stone

Answer 1

g 10 v 40. then. 0()2 -( 40)2 -- h -- 40 .40/20 --80. downwoard 80 thon tola distance 160

Answer 2

where V = 0

U = 40 m/s

a = -g m/s² = -10 m/s²

0 = (40)² -2 × 10 × S

• S = 80 m .