Question

a stone is thrown vertically upward and rises to a height 19.6m. Calculte a) the velocity with which the stone was thrown b) the time taken to reach the maximum height​

Answer 1

Explanation:

a = 9.8m/s²

s = 19.6m

v=0m/s

v²-u²=2as

0-u²=2(-9.8)(19.6)

-u²=-384.16

u=19.6m/s

a) the velocity with which the stone was thrown is 19.6m/s

b)v=u+at

0=19.6+(-9.8)t

-19.6=-9.8t

t=19.6/9.8

t=2sec

b)the time taken to reach the maximum height is 2 sec.