Question

a stone is thrown vertically upward direction with a velocity of 5 metre per second if acceleration of stone during its motion is 10 metre per second square in downward Direction What will be the height attained by stone and how much time would it would it take to reach there

Answer 1

Given :Initial velcoity=u=5m/sacceleration=10m/s2time=t=?Maximum height=h=?
a formula to be used:Maximum Height =Hmax=u²/2g=5x5/2x10=5/4m=1.25m
Time of ascent= Time taken to reach maximum height=u/g=5/10=1/2=0.5 sec
Hope it helps u dear