find the zero of the given polynomial (x-4)^2 - (x-6)^2
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Answered by
2
Hey
Your question : (x-4)^2 - (x-6)^2
Here is your answer,
To find the answer use the identity (a-b)^2=a^2 + b^2 -2ab.
(x-4)^2 = x^2 +16 -8x
(x-6)^2 = x^2 + 36 -12x
=(x^2 +16 -8x) - (x^2 + 36 -12x)
Multiplying the minus inside the bracket ,
=x^2 +16 -8x - x^2 -36 +12x
=4x -20
(4x-20)=0
4x=20
x=20/4
x=5
Hope it helps you!
Your question : (x-4)^2 - (x-6)^2
Here is your answer,
To find the answer use the identity (a-b)^2=a^2 + b^2 -2ab.
(x-4)^2 = x^2 +16 -8x
(x-6)^2 = x^2 + 36 -12x
=(x^2 +16 -8x) - (x^2 + 36 -12x)
Multiplying the minus inside the bracket ,
=x^2 +16 -8x - x^2 -36 +12x
=4x -20
(4x-20)=0
4x=20
x=20/4
x=5
Hope it helps you!
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Answered by
1
Answer:
Hiii friend,
(X-4)² - (X-6)²
=> (X)² + (4)² - 2 × X × 4 -(X² + (6)² - 2 × X × 6)
=> X²+16 -8X -(X²+36 -12X)
=> X²+16 -8X -X²-36+12X
=> 12X-8X-36+16
=> 4X - 20= 0
=> X = 20/4
=> X= 5
Step-by-step explanation:
#Hope it helped
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