Question

A stone is thrown vertically upward with a speed of 17.1 m/s how high does it rise ?

Answer 1

Answer:-

14.91m

Explanation:-

It is given that a stone is thrown vertically upwards with an initial speed of 17.1m/s and we need to find the maximum height to which the stone rises.

In this case :-

• Acceleration due to gravity (g) will be

-9.8m/s² as the stone is going against

gravity.

• Speed of the stone at the highest point

will be zero . Thus final speed (v) = 0.

By using the 3rd equation of motion, we get:-

=> v² - u² = 2gh

Where:-

• v is final speed of the stone.

• u is initial speed of the stone.

• g is acceleration due to gravity.

• h is the required height.

=> 0 - (17.1)² = 2(-9.8)h

=> -292.41 = -19.6h

=> h = -292.41/-19.6

=> h = 14.91m [approximately]

Thus the stone rises to a height of 14.91m .