Question

a stone is thrown vertically upward with a speed of 50ms-1 then the velocity of the stone after 5s i will mark correct answer as brainliest

Answer 1

Initially one stone is thrown up with a velocity of 50ms

Initially one stone is thrown up with a velocity of 50ms −1

Initially one stone is thrown up with a velocity of 50ms −1

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + at

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1 Hence one rock has a velocity of 0, and the other has a velocity of 100ms

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1 Hence one rock has a velocity of 0, and the other has a velocity of 100ms −1

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1 Hence one rock has a velocity of 0, and the other has a velocity of 100ms −1

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1 Hence one rock has a velocity of 0, and the other has a velocity of 100ms −1 Hence relative velocity is 100ms

Initially one stone is thrown up with a velocity of 50ms −1 Time it takes to reach stationary.v =0, u =50, a = -10,v = u + atSolving we get 5s.Meanwhile in 5seconds the other rock initially moving down with u =50ms −1 has now attained a velocity v.a=+10ms −2 v=u+at=50+5(10)=100ms −1 Hence one rock has a velocity of 0, and the other has a velocity of 100ms −1 Hence relative velocity is 100ms −1

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