Question

a stone is thrown vertically upward with a velocity of 30 metre per second if the acceleration due to gravity is 10 metre per second square what is the distance travelled by the particle during the first second of its motion​

Answer 1

Explanation:

$using \: s = ut + 1 \div 2at {}^{2} \\ s = 30 \times 1 + 1 \div 2 \times 10 \times (1) {}^{2} \\ s = 30 + 5 \\ s = 35$

MARK IT AS BRAINLIEST