Question

A stone is thrown vertically upward with a velocity of 4.9ms-1. calculate (1) the maximum height reached (2) the time taken to reach the maximum height (3) the velocity with which it return for the ground and(4) the time taken to reach the ground.

Answer 1

$h = {u}^{2} \div (2g)$
u is the velocity of the body =4.9 m/s
g is acceleration due to gravity 9.81m/s^2
h

2)
$t = u \div 9.81$
3)u=4.9m/s
4)2t =2×0.5=1sec