Question

a stone is thrown vertically upward with a velocity of 40 metre per second and Ispat back taking degree is equal to 10 metre per second square calculate the maximum height reached by the stone what is the net displacement done Total distance covered by the sun​

Answer 1

Answer:

Explanation:v=40

a=10,u=0

so,from first law of motion

v=u +at

40=0+10[t]

40/10 =t

4sec=t

from 2nd law of motion

s=ut+1/2at

s=0[4]+1/2[10][4]

s=0+20

s=20m