A stone is thrown vertically upward with a velocity of 40 m per second is cashback taking 9-10 second calculate the maximum distance
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According to the equation of motion under gravity v2 − u2 = 2gs Where, u = Initial velocity of the stone = 40 m/s v = Final velocity of the stone = 0 m/s s = Height of the stone g = Acceleration due to gravity = −10 ms−2 Let h be the maximum height attained by the stone. Therefore, 0 2 − 402 = 2(−10)ℎ ⇒ ℎ = (40×40) / 20 = 80 Therefore, total distance covered by the stone during its upward and downward journey = 80 + 80 = 160 m Net displacement during its upward and downward journey = 80 + (−80) = 0.
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