Physics, asked by monsterboyrk77, 5 months ago

A stone is thrown vertically upward with an initial velocity
of 30 m/s. Find the maximum height reached by the stone.
Also calculate the total distance covered by the stone.
(Take g= 10 m/s2

Answers

Answered by Anonymous

A stone is thrown vertically upward with an initial velocity

of 30 m/s. Find the maximum height reached by the stone. Also calculate the total distance covered by the stone. (Take g= 10 m/s2)

$\large { \rm{ \red{Given:- }}}$

$\large { \rm{ \blue{To \: Find:- }}}$

$\large { \rm{ \green{Directions:- }}}$

⟹At the highest point:-

${ \pink{ \bigstar}} { { \boxed{ \sf{Final \: Velocity=0}}}}$

${ \pink{ \bigstar}} { { \boxed{ \sf{Initial \: Velocity=30m/s}}}}$

Where,

${ { \bigstar}} { \orange{ \underline{ \sf{ {v}^{2} - {u}^{2} = 2as}}}}$

$\implies \tt {0}^{2} - {30}^{2} = 2as$

$\implies \tt 0 - 900 = 2 (-g)s$

$\implies \tt - 900 = 2 (-10)s$

$\implies \tt -900= -20s$

$\implies \tt 900= 20s$

$\implies \tt 45= s$

$\implies{ \boxed{ \sf{ s = 45}}}$

So, the maximum height reached is 45m.

$\implies \tt45 + 45 = 90m$

${ \orange{ \boxed{ \mathrm{ So, the \: total \: distance \: covered \: is \: 90m. }}}}$

Answered by Saurabhroyal

Answer:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v2−u2=2gs

0−402=−2×10×s

s=20160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.

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