A stone is thrown vertically upward with an initial velocity of 14ms-1 .after how long will the stone strike the ground
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Answer:
Explanation:
Initial velocity = 14 m/s
Final velocity = 0 m/s ( at its maximum height)
Acceleration = 9.8 m/s
From 1st equation = V = u + at
0 = 14 + 9.8t
-14 = 9.8t
t = -14/9.8 = 1.43 seconds( since time cannot be negative)
Since they ask time taken to reach ground, then it will be 2t = 2*1.43
2.86 seconds
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