a stone is thrown vertically upward with an initial velocity u from the top of a tower reaches, the ground with a velocity 3u the height of the Tower is? this question is taken from chapter kinematics, topic vertical motion
Answers
Answered by
5
let assume upward direction is - ve & downward is +ve
initial velocity= =-u
final velocity=+ 3u
acceleration= g
hence height of tower is
h = (v²-u²)/2g
= 9u²-u²/2g
= 8u²/2g
= 4u²/g
4*(initial velocity)²/g
initial velocity= =-u
final velocity=+ 3u
acceleration= g
hence height of tower is
h = (v²-u²)/2g
= 9u²-u²/2g
= 8u²/2g
= 4u²/g
4*(initial velocity)²/g
Similar questions