a stone is thrown vertically upward with an initial velocity u from the top of a tower it reaches the ground with velocity 3u you the height of the Tower is
Answers
Answered by
3
H = (v² - u²) / (2g)
H = (9u² - u²) / (2g)
H = 8u² / (2g)
H = 4u²/g
Height of the tower is 4u²/g
H = (9u² - u²) / (2g)
H = 8u² / (2g)
H = 4u²/g
Height of the tower is 4u²/g
Similar questions