A stone is thrown vertically upward with an initial velocity of 30m/s. Find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone.(take g=10m/s2)
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Answer:
45 = h
net displacement = 0
total distance = 2h = 90
Explanation:
V^2 = U^2 - 2gh
0 = 900 - 20h
45 = h
net displacement = 0
total distance = 2h = 90
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