Question

a stone is thrown vertically upward with an intial velocity u frok the top of a tower of height 12 u squre by g wiht what velocity does the stone reach the ground

Answer 1

Given: H=12u^2/g

Initial vel.=u

using formula v^2=u^2-2as

v^2=u^2+2*g*12u^2/g (since a= -g and s=h)

so v=5u ans.