A stone is thrown vertically upward with the velocity of 25m/s . How long does it take to reach maximuum height.Also find Height
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Answered by
9
Answer:
time taken to reach maximum height is 2.548 sec and Maximum height is 31.855 m
Explanation:
Initial velocity U= 25 m/s
at maximum height velocity, V= 0 m/s
Let the time taken to reach maximum height be t and maximum height be H.
V= U-gt
so 25-9.81.t=0
therefore t= 25/9.81
= 2.548 sec
Now,
H= Ut-1/2(gt^2)
=25x2.548-0.5x9.81x(2.548^2)
=31.855 m
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