A stone is thrown vertically upwards.When stone is at a height half of its maximum....
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Question :-
A stone is thrown vertically upwards.When stone is at a height half of its maximum height , velocity = ?
Answer :
Potential energy at the maximum height = kinetic energy at bottom .
Let max height be h.
So middle height = h / 2
Potential energy would be m g h / 2
Kinetic energy = potential energy .
= m g h / 2
K = 1 / 2 m v²
⇒ 1 / 2 m v² = 1 / 2 m g h
⇒ v² = g h
Hence the velocity will be g h
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