Physics, asked by tayab7684, 1 year ago

A stone is thrown vertically upwards with a speed of 10.0 m/s from the edge of the cliff 65m high. What will be its speed just before hitting? the bottom

Answers

Answered by gaurav7545
3

Explanation:

square of v =square of u + 2gh

square of v = 10*10+2*9.8*65

square of v = 100+1274

square of v= 1374

v =

 \sqrt{1374}

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