a stone is thrown vertically upwards with a velocity of 4.9 ms.calculate the time taken to reach the maximum height
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u=4.9 v=0
a=9.8
v=u +at
0=4.9+9.8t
4.9=9.8t
4.9/9.8 =t
1/2=t
or we can say 0.5 sec
a=9.8
v=u +at
0=4.9+9.8t
4.9=9.8t
4.9/9.8 =t
1/2=t
or we can say 0.5 sec
himanshujaat1:
thnxx bro
Answered by
0
answer is 0.5 seconds
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