a stone is thrown vertically upwards with a velocity of 40 m/s. if its downward accelarartionis 10m/s.what is the net displacment? calculate the distance covered by the stone befot it touches the ground
Answers
Answered by
1
u=40
a=10
v=0 at maximum height
using 2as=v*v- u*u we get
s=0-25/-2*10=1.25 m
1.25 is the distance as well as displacement
v*v means v to the power of 2 that is v's square
a=10
v=0 at maximum height
using 2as=v*v- u*u we get
s=0-25/-2*10=1.25 m
1.25 is the distance as well as displacement
v*v means v to the power of 2 that is v's square
Answered by
1
Please view the answer below. Hope it helps
Attachments:
Similar questions