a stone is thrown vertically upwards with a velocity of 49m/s calculate the height
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Let the initial velocity be u and distance be s and acceleration be a and final velocity be v.
Now as we know
u=0
v=49m/s
a=9.8m/so
Applying third law of motion
v²=u²+2as
(49)²=0 + 2*9.8*s
2401=19.6s
s=2401/19.6
s=122.5 m
Hope it will help you
Now as we know
u=0
v=49m/s
a=9.8m/so
Applying third law of motion
v²=u²+2as
(49)²=0 + 2*9.8*s
2401=19.6s
s=2401/19.6
s=122.5 m
Hope it will help you
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