A stone is thrown vertically upwards with an initial velocity, Ums-¹. It reaches a maximum height and returns to the ground. Find an equation for
I) the maximum height
ii) the velocity on hitting the ground
Answers
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2
1) Maximum height = u^2/2g
2) velocity on hitting the ground = u
Answered by
2
Answer:
1)Maximum height S=u2/2a.
2)Velocity on hitting the ground V=Initial velocity imparted to the stone U m/s.
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