Question

A stone is thrown vertically upwards with an initial velocity of 40m/s.
Find the maximum height reached by the stone. What is the net
displacement and total distance covered by the stone?

VERY URGENT PLS ANSWER
GR 9 QUESTION

Answer 1

Answer:

81.63 meters

Explanation:

We will use the following equation

${v}^{2} - {u}^{2} = 2as$

$initial \: velocity \: = 40m {sec}^{ - 1}$

At max height,final velocity is zero

${0}^{2} - {40}^{2} = 2 \times ( - 9.8) \times s$

(Negative Acceleration)

Solving,

$s = \frac{1600}{19.6}$

$s = 81.63m$

Total distance is 163.26 m

Total displacement is zero