Physics, asked by prabhakaranthiru1974, 4 months ago

A stone is thrown vertically upwards with an initial velocity of 40m/s^2 find the maximum height reached by the stone what is the net displacement and the total distance covered by the stone (g=10m/s^2)

Answers

Answered by thakurswati058

Answer:

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Explanation:

The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero. Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.

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A stone is thrown vertically upwards with an initial velocity of 40m/s^2 find the maximum height reached by the stone what is the net displacement and the total distance covered by the stone (g=10m/s^2)​

Answers

A stone is thrown vertically upwards with an initial velocity of 40m/s^2 find the maximum height reached by the stone what is the net displacement and the total distance covered by the stone (g=10m/s^2)