Question

In a
3
class of 140 students numbered 1 to 140, All even
numbered students ohted mathematis course, those
whase number Licisible by
pad Physik
caurse cand these whole number is
5 opted chemistry course. Then the number of Students
wha Led
not opt for any of the three courses
( 102
2012
3 (1)
(4 (38)​

Answer 1

Answer:

Correct option is

D

38

Let n(A)= number of students opted Mathematics =70,

n(B)= number of students opted Physics =46,

n(C)= number of students opted Chemistry =28,

n(A∩B)=23,

n(B∩C)=9,

n(A∩C)=14,

n(A∩B∩C)=4,

Now n(A∪B∪C)

=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

=70+46+28−23−9−14+4=102

Si number of students not opted for any course = Total −n(A∩B∩C)

=140−102=38.